Stirling Number of the Second Kind of 1
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Theorem
- $\ds {1 \brace n} = \delta_{1 n}$
where:
- $\ds {1 \brace n}$ denotes a Stirling number of the second kind
- $\delta_{1 n}$ is the Kronecker delta.
Proof
\(\ds {1 \brace n}\) | \(=\) | \(\ds n \times {0 \brace n} + {0 \brace n - 1}\) | Definition of Stirling Numbers of the Second Kind | |||||||||||
\(\ds \) | \(=\) | \(\ds n \times \delta_{0 n} + \delta_{0 \paren {n - 1} }\) | Definition of Stirling Numbers of the Second Kind | |||||||||||
\(\ds \) | \(=\) | \(\ds \delta_{0 \paren {n - 1} }\) | as $n \times \delta_{0 n}$ is either $n \times 0$ or $0 \times 1$ and so always $0$ | |||||||||||
\(\ds \) | \(=\) | \(\ds \delta_{1 n}\) | $0 = n - 1 \iff 1 = n$ |
$\blacksquare$