Strictly Positive Real Numbers are Closed under Multiplication/Proof 1

Theorem

The set $\R_{>0}$ of strictly positive real numbers is closed under multiplication:

$\forall a, b \in \R_{> 0}: a \times b \in \R_{> 0}$

Proof

Let $a, b \in \R_{> 0}$

We have that the Real Numbers form Ordered Integral Domain.

It follows from Positive Elements of Ordered Ring that:

$a \times b \in \R_{> 0}$.

$\blacksquare$