T2 Property is Hereditary
(Redirected from Subspace of Hausdorff Space is Hausdorff)
Jump to navigation
Jump to search
Theorem
Let $T = \struct {S, \tau}$ be a topological space which is a $T_2$ (Hausdorff) space.
Let $T_H = \struct {H, \tau_H}$, where $\O \subset H \subseteq S$, be a subspace of $T$.
Then $T_H$ is a $T_2$ (Hausdorff) space.
That is, the property of being a $T_2$ (Hausdorff) space is hereditary.
Proof
Let $T = \struct {S, \tau}$ be a $T_2$ (Hausdorff) space.
Then:
- $\forall x, y \in S, x \ne y: \exists U, V \in \tau: x \in U, y \in V: U \cap V = \O$
That is, for any two distinct elements $x, y \in S$ there exist disjoint open sets $U, V \in \tau$ containing $x$ and $y$ respectively.
We have that the set $\tau_H$ is defined as:
- $\tau_H := \set {U \cap H: U \in \tau}$
Let $x, y \in H$ such that $x \ne y$.
Then as $x, y \in S$ we have that:
- $\exists U, V \in \tau: x \in U, y \in V, U \cap V = \O$
As $x, y \in H$ we have that:
- $x \in U \cap H, y \in V \cap H: \paren {U \cap H} \cap \paren {V \cap H} = \O$
and so the $T_2$ axiom is satisfied in $H$.
$\blacksquare$
Sources
- 1975: W.A. Sutherland: Introduction to Metric and Topological Spaces ... (previous) ... (next): $4$: The Hausdorff condition: $4.2$: Separation axioms: Proposition $4.2.4 \ \text{(a)}$
- 1975: W.A. Sutherland: Introduction to Metric and Topological Spaces ... (previous) ... (next): $4$: The Hausdorff condition: Exercise $4.3: 2$
- 1978: Lynn Arthur Steen and J. Arthur Seebach, Jr.: Counterexamples in Topology (2nd ed.) ... (previous) ... (next): Part $\text I$: Basic Definitions: Section $2$: Separation Axioms: Functions, Products, and Subspaces