Sum of Fourth Powers of Sine and Cosine
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Theorem
- $\cos^4 x + \sin^4 x = 1 - 2 \cos^2 x \sin^2 x$
Proof 1
\(\ds \cos^4 x + \sin^4 x\) | \(=\) | \(\ds \dfrac {3 + 4 \cos 2 x + \cos 4 x} 8 + \dfrac {3 - 4 \cos 2 x + \cos 4 x} 8\) | Power Reduction Formula for 4th Power of Cosine, Power Reduction Formula for 4th Power of Sine | |||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac 3 4 + \dfrac {\cos 4 x} 4\) | simplification | |||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac 3 4 + \dfrac {8 \cos^4 x - 8 \cos^2 x + 1} 4\) | Quadruple Angle Formula for Cosine | |||||||||||
\(\ds \) | \(=\) | \(\ds 1 + 2 \cos^4 x - 2 \cos^2 x\) | simplification | |||||||||||
\(\ds \) | \(=\) | \(\ds 1 + 2 \cos^2 x \paren {1 - \sin^2 x} - 2 \cos^2 x\) | Sum of Squares of Sine and Cosine | |||||||||||
\(\ds \) | \(=\) | \(\ds 1 - 2 \sin^2 x \cos^2 x\) | simplification |
$\blacksquare$
Proof 2
\(\ds \cos^4 x + \sin^4 x\) | \(=\) | \(\ds \cos^2 x \paren {1 - \sin^2 x} + \sin^2 x \paren {1 - \cos^2 x}\) | Sum of Squares of Sine and Cosine | |||||||||||
\(\ds \) | \(=\) | \(\ds \cos^2 x + \sin^2 x - 2 \cos^2 x \sin^2 x\) | simplification | |||||||||||
\(\ds \) | \(=\) | \(\ds 1 - 2 \cos^2 x \sin^2 x\) | Sum of Squares of Sine and Cosine |
$\blacksquare$
Sources
- 1953: L. Harwood Clarke: A Note Book in Pure Mathematics ... (previous) ... (next): $\text V$. Trigonometry: Exercise $\text {XXXI}$: $4.$