Sum of Reciprocals of Cubes of Odd Integers Alternating in Sign
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Theorem
\(\ds \sum_{n \mathop = 0}^\infty \dfrac {\paren {-1}^n} {\paren {2 n + 1}^3}\) | \(=\) | \(\ds \frac 1 {1^3} - \frac 1 {3^3} + \frac 1 {5^3} - \frac 1 {7^3} + \cdots\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \frac {\pi^3} {32}\) |
Proof
By Half-Range Fourier Sine Series for $x \paren {\pi - x}$ over $\openint 0 \pi$:
- $\ds x \paren {\pi - x} = \frac 8 \pi \sum_{r \mathop = 0}^\infty \frac {\sin \paren {2 n + 1} x} {\paren {2 n + 1}^3}$
for $x \in \openint 0 \pi$.
Setting $x = \dfrac \pi 2$:
\(\ds \frac \pi 2 \paren {\pi - \frac \pi 2}\) | \(=\) | \(\ds \frac 8 \pi \sum_{n \mathop = 0}^\infty \frac {\sin \paren {2 n + 1} \frac \pi 2} {\paren {2 n + 1}^3}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \frac 8 \pi \sum_{n \mathop = 0}^\infty \frac {\sin \paren {n + \frac 1 2} \pi} {\paren {2 n + 1}^3}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \frac 8 \pi \sum_{n \mathop = 0}^\infty \frac {\paren {-1}^n} {\paren {2 n + 1}^3}\) | Sine of Half-Integer Multiple of Pi | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds \frac {\pi^2} 4 \times \frac \pi 8\) | \(=\) | \(\ds \sum_{n \mathop = 0}^\infty \frac {\paren {-1}^n} {\paren {2 n + 1}^3}\) |
whence the result.
$\blacksquare$
Sources
- 1968: Murray R. Spiegel: Mathematical Handbook of Formulas and Tables ... (previous) ... (next): $\S 19$: Series involving Reciprocals of Powers of Positive Integers: $19.28$