# Sum of Sequence of Cubes/Examples/36

## Examples of Sum of Sequence of Cubes

$36 = 1^3 + 2^3 + 3^3 = 6^2 = \paren {1 + 2 + 3}^2$

## Proof

 $\ds 36$ $=$ $\ds 6^2$ $\ds$ $=$ $\ds \paren {\dfrac {3 \times \paren {3 + 1}^2} 2}^2$ $\ds$ $=$ $\ds 1 + 8 + 27$ $\ds$ $=$ $\ds 1^3 + 2^3 + 3^3$

$\blacksquare$