Sum of Sequence of Odd Squares/Formulation 2
Jump to navigation
Jump to search
Theorem
- $\ds \forall n \in \Z_{> 0}: \sum_{i \mathop = 1}^n \paren {2 i - 1}^2 = \frac {4 n^3 - n} 3$
Proof
The proof proceeds by induction.
For all $n \in \Z_{> 0}$, let $\map P n$ be the proposition:
- $\ds \sum_{i \mathop = 1}^n \paren {2 i - 1}^2 = \frac {4 n^3 - n} 3$
Basis for the Induction
$\map P 1$ is the case:
\(\ds \sum_{i \mathop = 1}^1 \paren {2 i - 1}^2\) | \(=\) | \(\ds \paren {2 \times 1 - 1}^2\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 1^2\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac {\paren {4 \times 1 - 1}^3} 3\) |
Thus $\map P 1$ is seen to hold.
This is the basis for the induction.
Induction Hypothesis
Now it needs to be shown that, if $\map P k$ is true, where $k \ge 1$, then it logically follows that $\map P {k + 1}$ is true.
So this is the induction hypothesis:
- $\ds \sum_{i \mathop = 1}^k \paren {2 i - 1}^2 = \frac {4 k^3 - k} 3$
from which it is to be shown that:
- $\ds \sum_{i \mathop = 1}^{k + 1} \paren {2 i - 1}^2 = \frac {4 \paren {k + 1}^3 - \paren {k + 1} } 3$
Induction Step
This is the induction step:
\(\ds \sum_{i \mathop = 1}^{k + 1} \paren {2 i - 1}^2\) | \(=\) | \(\ds \sum_{i \mathop = 1}^k \paren {2 i - 1}^2 + \paren {2 \paren {k + 1} - 1}^2\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \frac {4 k^3 - k} 3 + \paren {2 k + 1}^2\) | Induction Hypothesis | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac {4 k^3 - k + 12 k^2 + 12 k + 3} 3\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \frac {\paren {k + 1} \paren {4 k^2 + 8 k + 3} } 3\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \frac {\paren {k + 1} \paren {4 \paren {k + 1}^2 - 1} } 3\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \frac {4 \paren {k + 1}^3 - \paren {k + 1} } 3\) |
So $\map P k \implies \map P {k + 1}$ and the result follows by the Principle of Mathematical Induction.
Therefore:
- $\ds \forall n \in \Z_{> 0}: \sum_{i \mathop = 1}^n \paren {2 i - 1}^2 = \frac {4 n^3 - n} 3$
$\blacksquare$
Sources
- 1977: Gary Chartrand: Introductory Graph Theory ... (previous) ... (next): Appendix $\text{A}.6$: Mathematical Induction: Problem Set $\text{A}.6$: $38$
- 1980: David M. Burton: Elementary Number Theory (revised ed.) ... (previous) ... (next): Chapter $1$: Some Preliminary Considerations: $1.1$ Mathematical Induction: Problems $1.1$: $1 \ \text {(d)}$