Supremum of Subset of Real Numbers/Examples/Example 7
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Example of Supremum of Subset of Real Numbers
The subset $S$ of the real numbers $\R$ defined as:
- $S = \set {x \in \R: x^3 < 8}$
admits a supremum:
- $\sup S = 2$
such that $\sup S \notin S$.
Proof
\(\ds x^3\) | \(<\) | \(\ds 8\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds x\) | \(<\) | \(\ds \sqrt [3] 8\) | |||||||||||
\(\ds \) | \(=\) | \(\ds 2\) |
Hence:
- $S = \set {x \in \R: x < 2}$
and it follows that:
- $\sup \set {x \in \R: x^3 < 8} = 2$
and it follows that $\sup S \notin S$.
$\blacksquare$
Sources
- 1975: W.A. Sutherland: Introduction to Metric and Topological Spaces ... (previous) ... (next): $1$: Review of some real analysis: Exercise $1.5: 4$