Talk:Cantor Set is Uncountable
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In fact, the $f$ in the informal proof isn't a bijection (for the representation of binary numbers isn't unique for a certain (countable) set of numbers, namely with finitely many nonzero $b_i$). --Lord_Farin 16:25, 16 November 2011 (CST)
- Goodness, so it isn't. Good call. --prime mover 16:40, 16 November 2011 (CST)