Talk:Complex Power Series/Examples/3^n-1 over 2^n+1

I think that the problem is in the third line of $a_n$, i.e. the $3/2$ should be $3^n/2^n$, and that is the limiting value, which is dependent upon n.

In the ratio test we would then have $|(3^{n-1}/2^{n-1})/(3^n/2^n)| = |1/(3/2)| = 2/3$ per the book.

I'm happy to make the relevant tweaks to the page if someone agrees that the above makes sense. --John Coupe (talk) 19:40, 29 December 2019 (EST)

Yes you are correct, that was an appalling mistake to have made. Please feel free to do the necessary. Thanks. --prime mover (talk) 01:33, 30 December 2019 (EST)