Talk:Generating Function for Natural Numbers

You're so boundlessly clever, you explain why it's valid to differentiate term by term. --prime mover (talk) 21:17, 1 May 2013 (UTC)

Yep, fair enough, that works. To be fair, the radius of convergence is not important in generating functions, as long as it is established that there is one. --prime mover (talk) 22:48, 1 May 2013 (UTC)

If the sequence is defined as $a_1 = 1$, then why isn't the generating function:

$\dfrac z {\left({1 - z}\right)^2}$

? --kc_kennylau (talk) 07:15, 29 December 2016 (EST)

We should have $a_i = i$. Either start with $a_0 = 0$ and have the indices of summation start at $0$, or start with $a_1 = 1$ and have the indices of summation all start with $1$. --GFauxPas (talk) 11:31, 29 December 2016 (EST)