Talk:Integer to Power of p-1 over 2 Modulo p

This is my first attempt at this: if I have broken any rules or conventions please advise and forgive me.

The first line of the theorem defines p as an odd prime.

The third line of the proof states: "if b^2 divides p, then b mod p = 0"

The seventh line of the proof states: "So either b+1 divides p or b−1 does."

Given the definition of p it seems to me that they should read: "if p divides b^2 , then b mod p = 0"

"So p divides b+1 or b−1 but not both."

--Joseph.odriscoll (talk) 20:56, 21 October 2012 (UTC) Joseph.odriscoll

Good catch. --prime mover (talk) 22:01, 21 October 2012 (UTC)

Thank you for noting, and for taking the time to notify us; the care you have shown by first posting to the talk page before editing the actual article already places you at a higher rank than most other new contributors.

Your verbose description of your issue is exemplary; a great deal could be won if everybody were so conscientious. For a point of improvement, you could start to use TeX (enclosed in dollar signs, as described on Help:Editing - note that you may have issues displaying that page: clicking Edit and then Preview has been a successful workaround of this (what we believe to be a) MediaWiki bug). Be assured that we always welcome thoughtful contributors whom are willing to learn. --Lord_Farin (talk) 22:04, 21 October 2012 (UTC)