Talk:Preimage of Singleton

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Can you review the statements that specify this result? I can't make sense of it. --prime mover 08:20, 11 August 2012 (UTC)

Better, but should:
Let $\mathcal R^{-1}\left({ \left\{ t \right\} }\right)$ denote the image of $\left\{ t \right\}$ under $\mathcal R$."
read:
Let $\mathcal R^{-1}\left({ \left\{ t \right\} }\right)$ denote the image of $\left\{ t \right\}$ under $\mathcal R^{-1}$."
? --prime mover 10:14, 11 August 2012 (UTC)
That should do it. --Lord_Farin 10:15, 11 August 2012 (UTC)