Talk:Union of Symmetric Differences

I have a result here that seems more appropriate for the name, namely:

$\left({A * B}\right) \cup \left({B * C}\right) = \left({A \cup B \cup C}\right) \setminus \left({A \cap B \cap C}\right)$

Question is, what to do with the current statement? --Lord_Farin 17:58, 12 March 2012 (EDT)

Pff. Shrug. "Symmetric Difference Subset of Union of Symmetric Differences"? --prime mover 18:20, 12 March 2012 (EDT)