Tangent of 300 Degrees
Jump to navigation
Jump to search
Theorem
- $\tan 300 \degrees = \tan \dfrac {5 \pi} 3 = -\sqrt 3$
where $\tan$ denotes tangent.
Proof
\(\ds \tan 300 \degrees\) | \(=\) | \(\ds \map \tan {360 \degrees - 60 \degrees}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds -\tan 60 \degrees\) | Tangent of Conjugate Angle | |||||||||||
\(\ds \) | \(=\) | \(\ds -\sqrt 3\) | Tangent of $60 \degrees$ |
$\blacksquare$
Sources
- 1968: Murray R. Spiegel: Mathematical Handbook of Formulas and Tables ... (previous) ... (next): $\S 5$: Trigonometric Functions: Exact Values for Trigonometric Functions of Various Angles