Top is Prime Element

From ProofWiki
Jump to navigation Jump to search

Theorem

Let $L = \struct {S, \wedge, \preceq}$ be a bounded above meet semilattice.


Then $\top$ is a prime element

where $\top$ denotes the greatest element of $L$.


Proof

Let $x, y \in S$ such that

$x \wedge y \preceq \top$

Thus by definition of greatest element:

$x \preceq \top$ or $y \preceq \top$

$\blacksquare$


Sources