Topology induced by Usual Metric on Positive Integers is Discrete
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Theorem
Let $\Z_{>0}$ be the set of (strictly) positive integers.
Let $d: \Z_{>0} \times \Z_{>0} \to \R$ be the usual (Euclidean) metric on $\Z_{>0}$.
Then the metric topology for $d$ is a discrete topology.
Proof
Let $\tau_d$ denote the metric topology for $d$.
Let $\epsilon \in \R_{>0}$ such that $\epsilon < 1$.
Let $a \in \Z_{>0}$.
Recall the definition of the open $\epsilon$-ball of $a$ in $\struct {\Z_{>0}, d}$:
- $\map {B_\epsilon} a := \set {x \in A: \map d {x, a} < \epsilon}$
But we have:
- $\forall x \in \Z_{>0}, x \ne a: \map d {x, a} \ge 1$
and so:
- $\forall x \in \Z_{>0}, x \ne a: x \notin \map {B_\epsilon} a$
It follows that:
- $\map {B_\epsilon} a := \set a$
Thus by definition of $\tau_d$:
- $\forall a \in \Z_{>0}: \set a \in \tau_d$
It follows from Basis for Discrete Topology that $\struct {\Z_{>0}, \tau_d}$ is a discrete topological space.
$\blacksquare$
Sources
- 1978: Lynn Arthur Steen and J. Arthur Seebach, Jr.: Counterexamples in Topology (2nd ed.) ... (previous) ... (next): Part $\text {II}$: Counterexamples: $32$. Special Subsets of the Real Line: $10$