Triangle Inequality/Complex Numbers/Examples/3 Arguments/Proof 3

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Example of Use of Triangle Inequality for Complex Numbers

For all $z_1, z_2, z_3 \in \C$:

$\cmod {z_1 + z_2 + z_3} \le \cmod {z_1} + \cmod {z_2} + \cmod {z_3}$


Proof

Let $z_1$, $z_2$ and $z_3$ be represented by the points $A$, $B$ and $C$ respectively in the complex plane.

From Geometrical Interpretation of Complex Addition, we can construct the parallelogram $OADB$ where:

$OA$ and $OB$ represent $z_1$ and $z_2$ respectively
$OD$ represents $z_1 + z_2$.

Also from Geometrical Interpretation of Complex Addition, we can construct the parallelogram $OCED$ where:

$OC$ and $OD$ represent $z_3$ and $z_1 + z_2$ respectively
$OD$ represents $z_1 + z_2 + z_3$.


Triangle-Inequality-Complex-3-Arguments.png


As $OADB$ is a parallelogram, we have that $OB = AD$.


The lengths of $OA$, $AD$ and $OD$ are:

\(\displaystyle OA\) \(=\) \(\displaystyle \cmod {z_1}\)
\(\displaystyle AD\) \(=\) \(\displaystyle \cmod {z_2}\)
\(\displaystyle OD\) \(=\) \(\displaystyle \cmod {z_1 + z_2}\)

But $OA$, $OB$ and $OD$ form the sides of a triangle.

Thus from Sum of Two Sides of Triangle Greater than Third Side:

$\cmod {z_1 + z_2} \le \cmod {z_1} + \cmod {z_2}$


Similarly, as $OCED$ is a parallelogram, we have that $OD = CE$.


The lengths of $OC$, $CE$ and $OE$ are:

\(\displaystyle OC\) \(=\) \(\displaystyle \cmod {z_3}\)
\(\displaystyle CE\) \(=\) \(\displaystyle \cmod {z_2 + z_2}\)
\(\displaystyle OE\) \(=\) \(\displaystyle \cmod {z_1 + z_2 + z_3}\)

But $OC$, $CE$ and $OE$ form the sides of a triangle.

Thus from Sum of Two Sides of Triangle Greater than Third Side:

$\cmod {z_1 + z_2 + z_3} \le \cmod {z_1 + z_2} + \cmod {z_3}$

The result follows.

$\blacksquare$


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