Trivial Group is Cyclic Group
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Theorem
The trivial group is a cyclic group.
Proof
In Trivial Group is Group it is shown that the algebraic structure $\struct {\set e, \circ}$ such that $e \circ e = e$ is in fact a group.
It remains to be shown that it is cyclic.
In order for $G$ to be a cyclic group, every element $x$ of $G$ has to be expressible in the form $x = g^n$ for some $g \in G$ and some $n \in \Z$.
In this case, for every integer $n$, every element of $G$ can be expressed in the form $e^n$.
Thus $G$ is trivially a cyclic group.
$\blacksquare$
Sources
- 1965: J.A. Green: Sets and Groups ... (previous) ... (next): $\S 5.4$. Cyclic groups: Example $100$
- 1974: Thomas W. Hungerford: Algebra ... (previous) ... (next): $\S 1.2$