Underlying Set of Topological Space is Closed

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Let $T = \struct {S, \tau}$ be a topological space.

Then the underlying set $S$ of $T$ is closed in $T$.


From the definition of closed set, $U$ is open in $T = \struct {S, \tau}$ if and only if $S \setminus U$ is closed in $T$.

From Empty Set is Element of Topology, $\varnothing$ is open in $T$.

From Set Difference with Empty Set is Self, we have $S \setminus \varnothing = S$, so $S$ is closed in $T$.