Union of Union of Relation is Union of Domain with Image
Jump to navigation
Jump to search
Theorem
Let $V$ be a basic universe.
Let $\RR \subseteq V \times V$ be a relation.
Let $\Dom \RR$ denote the domain of $\RR$.
Then:
- $\map \bigcup {\bigcup \RR} = \Dom \RR \cup \Img \RR$
where:
- $\bigcup \RR$ denotes the union of $\RR$
- $\Dom \RR$ denotes the domain of $\RR$
- $\Img \RR$ denotes the image of $\RR$.
Proof
\(\ds \bigcup \RR\) | \(=\) | \(\ds \set {z: \exists \tuple {x, y} \in \RR: z \in \tuple {x, y} }\) | Definition of Union of Class | |||||||||||
\(\ds \) | \(=\) | \(\ds \set {z: \exists \set {\set x, \set {x, y} } \in \RR: z \in \tuple {x, y} }\) | Definition of Kuratowski Formalization of Ordered Pair | |||||||||||
\(\ds \) | \(=\) | \(\ds \set {\set x, \set {x, y}: x \in \Dom \RR, \tuple {x, y} \in \RR}\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds \map \bigcup {\bigcup \RR}\) | \(=\) | \(\ds \set {z: \exists X \in \bigcup \RR: z \in X}\) | Definition of Union of Class | ||||||||||
\(\ds \) | \(=\) | \(\ds \set {x, y: x \in \Dom \RR, \tuple {x, y} \in \RR}\) | Definition of $\bigcup \RR$ | |||||||||||
\(\ds \) | \(=\) | \(\ds \set {x, y: x \in \Dom \RR, y \in \Img \RR}\) | Definition of Image of Relation | |||||||||||
\(\ds \) | \(=\) | \(\ds \set {x: x \in \Dom \RR} \cup \set {y: y \in \Img \RR}\) | Definition of Class Union | |||||||||||
\(\ds \) | \(=\) | \(\ds \Dom \RR \cup \Img \RR\) |
$\blacksquare$