Union of Unordered Tuples
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Theorem
Let $x_1, \dots, x_n, x_{n+1}, \dots, x_m$ be arbitrary.
Then
- $\set {x_1, \dots, x_n} \cup \set {x_{n + 1}, \dots, x_m} = \set {x_1, \dots, x_n, x_{n + 1}, \dots, x_m}$
Proof
Let $a$ be arbitrary.
- $a \in \set {x_1, \dots, x_n} \cup \set {x_{n + 1}, \dots, x_m}$
- $a \in \set {x_1, \dots, x_n}$ or $a \in \set {x_{n + 1}, \dots, x_m}$ by definition of union
- $a = x_1 \lor \dots \lor a = x_n$ or $a = x_{n + 1} \lor \dots \lor a = x_m$ by definition of unordered tuple
- $a = x_1 \lor \dots \lor a = x_n \lor a = x_{n + 1} \lor \dots \lor a = x_m$
- $a \in \set {x_1, \dots, x_n, x_{n + 1}, \dots, x_m}$ by definition of unordered tuple
Thus result follows by definition of set equality.
$\blacksquare$