Vector Cross Product Operator is Bilinear
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Theorem
Let $\mathbf u$, $\mathbf v$ and $\mathbf w$ be vectors in a vector space $\mathbf V$ of $3$ dimensions:
\(\ds \mathbf u\) | \(=\) | \(\ds u_i \mathbf i + u_j \mathbf j + u_k \mathbf k\) | ||||||||||||
\(\ds \mathbf v\) | \(=\) | \(\ds v_i \mathbf i + v_j \mathbf j + v_k \mathbf k\) | ||||||||||||
\(\ds \mathbf w\) | \(=\) | \(\ds w_i \mathbf i + w_j \mathbf j + w_k \mathbf k\) |
where $\left({\mathbf i, \mathbf j, \mathbf k}\right)$ is the standard ordered basis of $\mathbf V$.
Let $c$ be a real number.
Then:
- $\left({c \mathbf u + \mathbf v}\right) \times \mathbf w = c \left({ \mathbf u \times \mathbf w}\right) + \mathbf v \times \mathbf w$
Proof
\(\ds \left({c \mathbf u + \mathbf v}\right) \times \mathbf w\) | \(=\) | \(\ds \begin{vmatrix} \mathbf i & \mathbf j & \mathbf k \\ c u_i + v_i & c u_j + v_j & c u_k + v_k \\ w_i & w_j & w_k \end{vmatrix}\) | Definition of Vector Cross Product | |||||||||||
\(\ds \) | \(=\) | \(\ds \begin{vmatrix} \mathbf i & \mathbf j & \mathbf k \\ c u_i & c u_j & c u_k \\ w_i & w_j & w_k \end{vmatrix} + \begin{vmatrix} \mathbf i& \mathbf j & \mathbf k \\ v_i & v_j & v_k \\ w_i & w_j & w_k \end{vmatrix}\) | Determinant as Sum of Determinants | |||||||||||
\(\ds \) | \(=\) | \(\ds c \begin{vmatrix} \mathbf i & \mathbf j & \mathbf k \\ u_i & u_j & u_k \\ w_i & w_j & w_k \end{vmatrix} + \begin{vmatrix} \mathbf i & \mathbf j & \mathbf k \\ v_i & v_j & v_k \\ w_i & w_j & w_k \end{vmatrix}\) | Determinant with Row Multiplied by Constant | |||||||||||
\(\ds \) | \(=\) | \(\ds c \left({\mathbf u \times \mathbf w}\right) + \mathbf v \times \mathbf w\) | Definition of Vector Cross Product |
$\blacksquare$