Von Neumann Hierarchy is Cumulative

From ProofWiki
Jump to navigation Jump to search



Theorem

For any two ordinals $x$ and $y$,

If $x < y$ then $V(x) \subsetneqq V(y)$.


Proof

By Von Neumann Hierarchy Comparison, $V(x) \in V(y)$. (1)

By (1) and the Axiom:Axiom of Foundation, $V(x) \ne V(y)$.

Furthermore, by (1) and Von Neumann Hierarchy is Supertransitive,