Way Below Relation is Transitive

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Theorem

Let $\left({S, \preceq}\right)$ be an ordered set.

Let $x, y, z \in S$ such that

$x \ll y \ll z$


Then

$x \ll z$


Proof

By Way Below implies Preceding:

$x \preceq y$

By definition of reflexivity:

$z \preceq z$

Thus by Preceding and Way Below implies Way Below:

$x \ll z$

$\blacksquare$


Sources