Zero of Power Set with Union
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Theorem
Let $S$ be a set and let $\powerset S$ be its power set.
Consider the algebraic structure $\struct {\powerset S, \cup}$, where $\cup$ denotes set union.
Then $S$ serves as the zero element for $\struct {\powerset S, \cup}$.
Proof
We note that by Set is Subset of Itself, $S \subseteq S$ and so $S \in \powerset S$ from the definition of the power set.
From Union with Superset is Superset‎, we have:
- $A \subseteq S \iff A \cup S = S = S \cup A$.
By definition of power set:
- $A \subseteq S \iff A \in \powerset S$
So:
- $\forall A \in \powerset S: A \cup S = S = S \cup A$
Thus we see that $S$ acts as the zero.
$\blacksquare$
Sources
- 1964: W.E. Deskins: Abstract Algebra ... (previous) ... (next): Exercise $1.4: \ 10$
- 1965: J.A. Green: Sets and Groups ... (previous) ... (next): $\S 4.3$. Units and zeros: Example $75$