Henry Ernest Dudeney/Puzzles and Curious Problems/159 - The Year 1927/Solution
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Puzzles and Curious Problems by Henry Ernest Dudeney: $159$
- The Year $1927$
- Can you find values for $p$ and $q$ such that $p^q - q^p = 1927$?
- To make it perfectly clear, we will give an example for the year $1844$, where $p = 3$ and $q = 7$:
- $3^7 - 7^3 = 1844$
- Can you express $1927$ in the same curious way?
Solution
- $2^{11} - 11^2 = 2048 - 121 = 1927$
Sources
- 1932: Henry Ernest Dudeney: Puzzles and Curious Problems ... (previous) ... (next): Solutions: $159$. -- The Year $1927$
- 1968: Henry Ernest Dudeney: 536 Puzzles & Curious Problems ... (previous) ... (next): Answers: $226$. The Year $1927$