Knaster-Tarski Lemma/Corollary/Power Set/Proof 1
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Theorem
Let $S$ be a set.
Let $\powerset S$ be the power set of $S$.
Let $f: \powerset S \to \powerset S$ be a $\subseteq$-increasing mapping.
That is, suppose that for all $T, U \in \powerset S$:
- $T \subseteq U \implies \map f T \subseteq \map f U$
Then $f$ has a fixed point.
Proof
By the Knaster-Tarski Lemma: Power Set, $f$ has a least fixed point.
Thus it has a fixed point.
$\blacksquare$
Source of Name
This entry was named for Bronisław Knaster and Alfred Tarski.
Sources
- 2010: Raymond M. Smullyan and Melvin Fitting: Set Theory and the Continuum Problem (revised ed.): Lemma $9.2.2$