Projection is Surjection/Family of Sets
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Theorem
Let $\family {S_\alpha}_{\alpha \mathop \in I}$ be a family of sets.
Let $\ds \prod_{\alpha \mathop \in I} S_\alpha$ be the Cartesian product of $\family {S_\alpha}_{\alpha \mathop \in I}$.
Let each of $S_\alpha$ be non-empty.
For each $\beta \in I$, let $\ds \pr_\beta: \prod_{\alpha \mathop \in I} S_\alpha \to S_\beta$ be the $\beta$th projection on $\ds S = \prod_{\alpha \mathop \in I} S_\alpha$.
Then $\pr_\beta$ is a surjection.
Proof
Consider the $\beta$th projection.
Let $x_\beta \in S_\beta$.
Let $\map x \beta = x_\beta$
Suppose $\gamma \in I: \gamma \ne \beta$.
As $S_\gamma \ne \O$ it is possible to use the axiom of choice to choose $\map x \gamma \in S_\gamma$.
Then:
- $\ds x \in \prod_{\alpha \mathop \in I} S_\alpha$
and:
- $\map {\pr_\beta} x = \map x \beta$
Hence the result.
$\blacksquare$
Sources
- 1975: Bert Mendelson: Introduction to Topology (3rd ed.) ... (previous) ... (next): Chapter $1$: Theory of Sets: $\S 10$: Arbitrary Products