4851

From ProofWiki
Jump to navigation Jump to search

Previous  ... Next

Number

$4851$ (four thousand, eight hundred and fifty-one) is:

$3^2 \times 7^2 \times 11$


The $21$st pentagonal pyramidal number after $1$, $6$, $12$, $40$, $75$, $126$, $196$, $288$, $405$, $550$, $726$, $936$, $1183$, $1470$, $1800$, $2176$, $2601$, $3078$, $3610$, $4200$:
$4851 = \ds \sum_{k \mathop = 1}^{21} \dfrac {k \paren {3 k - 1} } 2 = \dfrac {21^2 \paren {21 + 1} } 2$


The $98$th triangular number after $1$, $3$, $6$, $10$, $15$, $\ldots$, $4095$, $4186$, $4278$, $4371$, $4465$, $4560$, $4656$, $4753$:
$4851 = \ds \sum_{k \mathop = 1}^{98} k = \dfrac {98 \times \paren {98 + 1} } 2$


Also see