Arctangent is of Exponential Order Zero
Jump to navigation
Jump to search
Theorem
Let $\arctan: \R \to \openint {-\dfrac \pi 2} {\dfrac \pi 2}$ be the real arctangent.
Then $\arctan$ is of exponential order $0$.
Proof
Follows from Function with Limit at Infinity of Exponential Order Zero.
$\blacksquare$