Area of Triangle in Terms of Side and Altitude/Dissection Proof
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Theorem
The area of a triangle $\triangle ABC$ is given by:
- $\dfrac {c \cdot h_c} 2 = \dfrac {b \cdot h_b} 2 = \dfrac {a \cdot h_a} 2$
where:
Dissection Proof
Sources
- 2008: David Nelson: The Penguin Dictionary of Mathematics (4th ed.) ... (previous) ... (next): dissection proof