Category:Total Force on Point Charge from 2 Point Charges

Let $q_1$, $q_2$ and $q_3$ be point charges.

Let $\mathbf F_{ij}$ denote the electrostatic force exerted on $q_j$ by $q_i$.

Let $\mathbf F_i$ denote the electrostatic force exerted on $q_i$ by the combined action of the other two point charges.

Then the electrostatic force $\mathbf F_1$ exerted on $q_1$ by the combined action of $q_2$ and $q_3$ is given by:

$\ds \mathbf F_1$

$=$

$\ds \mathbf F_{21} + \mathbf F_{31}$

$\ds $

$=$

$\ds \dfrac {q_2 q_1} {4 \pi \varepsilon_0 {r_{2 1} }^3} \mathbf r_{2 1} + \dfrac {q_3 q_1} {4 \pi \varepsilon_0 {r_{3 1} }^3} \mathbf r_{3 1}$

where:

$\mathbf F_{21} + \mathbf F_{31}$ denotes the vector sum of $\mathbf F_{21}$ and $\mathbf F_{31}$

$\mathbf r_{ij}$ denotes the displacement from $q_i$ to $q_j$

$r_{ij}$ denotes the distance between $q_i$ and $q_j$

$\varepsilon_0$ denotes the vacuum permittivity.

Pages in category "Total Force on Point Charge from 2 Point Charges"

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