Characterization of Cauchy Sequence in Topological Vector Space in terms of Local Basis
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Theorem
Let $\struct {X, \tau}$ be a topological vector space.
Let $\BB$ be a local basis for $\mathbf 0_X$ in $\struct {X, \tau}$.
Let $\sequence {x_n}_{n \mathop \in \N}$ be a sequence.
Then $\sequence {x_n}_{n \mathop \in \N}$ is Cauchy if and only if:
- for each $V \in \BB$ there exists $N \in \N$ such that $x_n - x_m \in V$ for $n, m \ge N$.
Proof
Necessary Condition
Suppose that $\sequence {x_n}_{n \mathop \in \N}$ is Cauchy.
Then:
- for each open neighborhood $V$ of $\mathbf 0_X$ there exists $N \in \N$ such that:
- $x_n - x_m \in V$ for each $n, m \ge N$.
Since $\BB$ consists of open neighbourhoods of $\mathbf 0_X$, we in particular have:
- for each $V \in \BB$ there exists $N \in \N$ such that $x_n - x_m \in V$ for $n, m \ge N$.
$\Box$
Sufficient Condition
Suppose that:
- for each $V \in \mathcal B$ there exists $N \in \N$ such that $x_n - x_m \in V$ for $n, m \ge N$.
Let $U$ be an open neighborhood of $\mathbf 0_X$.
Then there exists $V \in \mathcal B$ such that $V \subseteq U$.
Then there exists $N \in \N$ such that $x_n - x_m \in V \subseteq U$ for $n, m \ge N$.
So $\sequence {x_n}_{n \mathop \in \N}$ is Cauchy.
$\blacksquare$