Characterization of Paracompactness in T3 Space/Lemma 2

From ProofWiki
Jump to navigation Jump to search



Theorem

Let $T = \struct{X, \tau}$ be a topological space.


Let $\AA$ be a locally finite cover of $T$.


Let $\BB = \set{A^- : A \in \AA}$ be locally finite, where $A^-$ denotes the closure of $A$ in $T$.


Then:

$\BB$ is a cover of $T$ consisting of closed sets


Proof

Let $x \in X$.


By definition of refinement:

$\AA$ is a cover of $X$


By definition of cover of set:

$\exists A \in \AA : x \in A$


From Set is Subset of its Topological Closure:

$A \subseteq A^-$


By definition of subset:

$x \in A^-$


By definition of $\BB$:

$A^- \in \BB$


Since $x$ was arbitrary, $\BB$ is a cover of $T$ by definition.


From Topological Closure is Closed, every element of $\BB$ is closed in $T$

$\blacksquare$