Condition for Nu Function to be 1
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Theorem
Let:
- $n = \displaystyle \prod_{i \mathop = 1}^s p_i^{m_i}$
where $p_1, p_2, \ldots, p_s$ are distinct primes.
Then:
- $(1): \quad m_1, m_2, \ldots, m_s = 1$, that is, $n$ is square-free
- $(2): \quad \forall i, j \in \set {1, 2, \ldots, s}: p_i \not \equiv 1 \pmod {p_j}$
Proof
Examples
Group of Order $15$ is Cyclic Group
Let $G$ be a group whose order is $15$.
Then $G$ is cyclic.
Sources
- 1978: John S. Rose: A Course on Group Theory ... (previous) ... (next): $1$: Introduction to Finite Group Theory: $1.4$