Condition for Solubility of Galois Group of Polynomial
Jump to navigation
Jump to search
Theorem
Let $P$ be a polynomial.
Let $G$ be the Galois group of $P$.
Then $G$ is soluble if and only if the roots of $P$ can be obtained from the coefficients of $P$ using just the arithmetic operations and raising to powers of the form $\dfrac 1 n$ for a natural number $n$.
Proof
![]() | This theorem requires a proof. You can help $\mathsf{Pr} \infty \mathsf{fWiki}$ by crafting such a proof. To discuss this page in more detail, feel free to use the talk page. When this work has been completed, you may remove this instance of {{ProofWanted}} from the code.If you would welcome a second opinion as to whether your work is correct, add a call to {{Proofread}} the page. |
Sources
- 1998: David Nelson: The Penguin Dictionary of Mathematics (2nd ed.) ... (previous) ... (next): Galois theory
- 2008: David Nelson: The Penguin Dictionary of Mathematics (4th ed.) ... (previous) ... (next): Galois theory