Cube Number as Sum of Three Consecutive Odd Squares
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Contents
Theorem
- $1331 = 11^3 = 19^2 + 21^2 + 23^2$
Proof
| \(\displaystyle 19^2 + 21^2 + 23^2\) | \(=\) | \(\displaystyle 361 + 441 + 529\) | |||||||||||
| \(\displaystyle \) | \(=\) | \(\displaystyle 1331\) |
$\blacksquare$
Historical Note
In his Curious and Interesting Numbers, 2nd ed. of $1997$, David Wells attributes this result to Michal Stajsczak, but gives no context.
Sources
- 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $1331$
