Cube Number as Sum of Three Consecutive Odd Squares

Theorem

$1331 = 11^3 = 19^2 + 21^2 + 23^2$

Proof

\(\ds 19^2 + 21^2 + 23^2\)

\(=\)

\(\ds 361 + 441 + 529\)

\(\ds \)

\(=\)

\(\ds 1331\)

$\blacksquare$

Historical Note

In his Curious and Interesting Numbers, 2nd ed. of $1997$, David Wells attributes this result to Michal Stajsczak, but gives no context.

Sources

• 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $1331$