# Definite Integral of Constant Multiple of Real Function/Proof 1

Jump to navigation
Jump to search

## Theorem

Let $f$ be a real function which is integrable on the closed interval $\closedint a b$.

Let $c \in \R$ be a real number.

Then:

- $\displaystyle \int_a^b c \, \map f x \rd x = c \int_a^b \map f x \rd x$

## Proof

Let $F$ be a primitive of $f$ on $\closedint a b$.

By Primitive of Constant Multiple of Function, $H = c F$ is a primitive of $c f$ on $\closedint a b$.

Hence by the Fundamental Theorem of Calculus:

\(\displaystyle \int_a^b c \map f x \rd x\) | \(=\) | \(\displaystyle \bigintlimits {c \map F x} a b\) | |||||||||||

\(\displaystyle \) | \(=\) | \(\displaystyle c \bigintlimits {\map F x} a b\) | |||||||||||

\(\displaystyle \) | \(=\) | \(\displaystyle c \int_a^b \map f x \rd x\) |

$\blacksquare$