Derivative of Composite Function/Examples/Root of x + 1 over x - 1
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Example of Derivative of Composite Function
- $\map {\dfrac \d {\d x} } {\sqrt {\dfrac {x + 1} {x - 1} } } = -\dfrac 1 {\sqrt {\paren {x + 1} \paren {x - 1}^3} }$
Proof
Let $u = \dfrac {x + 1} {x - 1}$.
Let $y = u^{1/2}$.
Thus we have:
- $y = \paren {\dfrac {x + 1} {x - 1} }^{1/2}$
and so:
\(\ds \dfrac {\d y} {\d x}\) | \(=\) | \(\ds \dfrac {\d y} {\d u} \dfrac {\d u} {\d x}\) | Derivative of Composite Function | |||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac 1 {2 \sqrt u} \paren {-\dfrac 2 {\paren {x - 1}^2} }\) | Power Rule for Derivatives, Derivative of $\dfrac {x + 1} {x - 1}$ | |||||||||||
\(\ds \) | \(=\) | \(\ds -\dfrac 1 {\sqrt {\dfrac {x + 1} {x - 1} } \paren {x - 1}^2}\) | simplification | |||||||||||
\(\ds \) | \(=\) | \(\ds -\dfrac 1 {\sqrt {\paren {x + 1} \paren {x - 1}^3} }\) | simplification |
$\blacksquare$
Sources
- 1953: L. Harwood Clarke: A Note Book in Pure Mathematics ... (previous) ... (next): $\text {II}$. Calculus: Differentiation: Exercises $\text {IX}$: $18$.