Disjunction with Contradiction

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Theorem

A disjunction with a contradiction:

$p \lor \bot \dashv \vdash p$


Proof by Natural Deduction

By the tableau method of natural deduction:

$p \lor \bot \vdash p$
Line Pool Formula Rule Depends upon Notes
1 1 $p \lor \bot$ Premise (None)
2 2 $p$ Assumption (None)
3 3 $\bot$ Assumption (None)
4 3 $p$ Rule of Explosion: $\bot \mathcal E$ 3
5 1 $p$ Proof by Cases: $\text{PBC}$ 1, 2 – 2, 3 – 4 Assumptions 2 and 3 have been discharged

$\Box$


By the tableau method of natural deduction:

$p \vdash p \lor \bot$
Line Pool Formula Rule Depends upon Notes
1 1 $p$ Premise (None)
2 1 $p \lor \bot$ Rule of Addition: $\lor \mathcal I_1$ 1

$\blacksquare$


Proof by Truth Table

We apply the Method of Truth Tables to the proposition.

As can be seen by inspection, in each case, the truth values in the appropriate columns match for all boolean interpretations.

$\begin{array}{|c|ccc||c|ccc|} \hline \bot & p & p & \lor & \bot \\ \hline F & F & F & F & F \\ F & T & T & T & F \\ \hline \end{array}$

$\blacksquare$


Sources