Distance-Preserving Mapping is Injection of Metric Spaces

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Theorem

Let $M_1 = \left({A_1, d_1}\right)$ and $M_2 = \left({A_2, d_2}\right)$ be metric spaces.

Let $\phi: M_1 \to M_2$ be a distance-preserving mapping.

Then $\phi$ is an injection.


Proof

Let $a, b \in A_1$ and suppose that $\phi \paren {a} = \phi \paren{b}$.

Then by the definition of a metric space:

$d_2 \tuple{ \phi \paren a, \phi \paren b } = 0$


By the definition of a distance-preserving mapping then:

$d_1 \tuple{ a, b } = 0$

Thus by the definition of a metric space:

$a = b$


Hence $\phi$ is injective.

$\blacksquare$