Division on Numbers is Not Associative

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Theorem

The operation of division on the numbers is not associative.

That is, in general:

$a \div \paren {b \div c} \ne \paren {a \div b} \div c$


Proof

By definition of division:

\(\ds a \div \paren {b \div c}\) \(=\) \(\ds a \times \paren {\dfrac 1 {b \times \dfrac 1 c} }\)
\(\ds \) \(=\) \(\ds a \times \paren {\dfrac c b}\)
\(\ds \) \(=\) \(\ds \dfrac {a c} b\)


\(\ds \paren {a \div b} \div c\) \(=\) \(\ds \paren {a \times \dfrac 1 b} \times \dfrac 1 c\)
\(\ds \) \(=\) \(\ds \dfrac a {b c}\)

So we see that:

$a \div \paren {b \div c} = \paren {a \div b} \div c \iff c = 1$

and so in general:

$a \div \paren {b \div c} \ne \paren {a \div b} \div c$

$\blacksquare$


Sources