Division on Numbers is Not Associative
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Theorem
The operation of division on the numbers is not associative.
That is, in general:
- $a \div \paren {b \div c} \ne \paren {a \div b} \div c$
Proof
By definition of division:
\(\ds a \div \paren {b \div c}\) | \(=\) | \(\ds a \times \paren {\dfrac 1 {b \times \dfrac 1 c} }\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds a \times \paren {\dfrac c b}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac {a c} b\) |
\(\ds \paren {a \div b} \div c\) | \(=\) | \(\ds \paren {a \times \dfrac 1 b} \times \dfrac 1 c\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac a {b c}\) |
So we see that:
- $a \div \paren {b \div c} = \paren {a \div b} \div c \iff c = 1$
and so in general:
- $a \div \paren {b \div c} \ne \paren {a \div b} \div c$
$\blacksquare$
Sources
- 1998: David Nelson: The Penguin Dictionary of Mathematics (2nd ed.) ... (previous) ... (next): associative
- 2008: David Nelson: The Penguin Dictionary of Mathematics (4th ed.) ... (previous) ... (next): associative