Divisor Sum of 10,856

From ProofWiki
Jump to navigation Jump to search

Example of Divisor Sum of Integer

$\map {\sigma_1} {10 \, 856} = 21 \, 600$

where $\sigma_1$ denotes the divisor sum function.


Proof

From Divisor Sum of Integer:

$\ds \map {\sigma_1} n = \prod_{1 \mathop \le i \mathop \le r} \frac {p_i^{k_i + 1} - 1} {p_i - 1}$

where $n = \ds \prod_{1 \mathop \le i \mathop \le r} p_i^{k_i}$ denotes the prime decomposition of $n$.


We have that:

$10 \, 856 = 2^3 \times 23 \times 59$


Hence:

\(\ds \map {\sigma_1} {10 \, 856}\) \(=\) \(\ds \frac {2^4 - 1} {2 - 1} \times \paren {23 + 1} \times \paren {59 + 1}\)
\(\ds \) \(=\) \(\ds \frac {15} 1 \times 24 \times 60\)
\(\ds \) \(=\) \(\ds \paren {3 \times 5} \times \paren {2^3 \times 3} \times \paren {2^2 \times 3 \times 5}\)
\(\ds \) \(=\) \(\ds 2^5 \times 3^3 \times 5^2\)
\(\ds \) \(=\) \(\ds 21 \, 600\)

$\blacksquare$