Divisor Sum of 14,536
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Example of Divisor Sum of Integer
- $\map {\sigma_1} {14 \, 536} = 28 \, 800$
where $\sigma_1$ denotes the divisor sum function.
Proof
- $\ds \map {\sigma_1} n = \prod_{1 \mathop \le i \mathop \le r} \frac {p_i^{k_i + 1} - 1} {p_i - 1}$
where $n = \ds \prod_{1 \mathop \le i \mathop \le r} p_i^{k_i}$ denotes the prime decomposition of $n$.
We have that:
- $14 \, 536 = 2^3 \times 23 \times 79$
Hence:
\(\ds \map {\sigma_1} {14 \, 536}\) | \(=\) | \(\ds \frac {2^4 - 1} {2 - 1} \times \frac {23^2 - 1} {23 - 1} \times \frac {79^2 - 1} {79 - 1}\) | Divisor Sum of Integer | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac {15} 1 \times \frac {24 \times 22} {22} \times \frac {80 \times 78} {78}\) | Difference of Two Squares | |||||||||||
\(\ds \) | \(=\) | \(\ds 15 \times 24 \times 80\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \paren {3 \times 5} \times \paren {2^3 \times 3} \times \paren {2^4 \times 5}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 2^7 \times 3^2 \times 5^2\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 28 \, 800\) |
$\blacksquare$