Divisor Sum of 15,435

From ProofWiki
Jump to navigation Jump to search

Example of Divisor Sum of Integer

$\map {\sigma_1} {15 \, 435} = 31 \, 200$

where $\sigma_1$ denotes the divisor sum function.


Proof

We have that:

$15 \, 435 = 3^2 \times 5 \times 7^3$


Hence:

\(\ds \map {\sigma_1} {15 \, 435}\) \(=\) \(\ds \dfrac {3^3 - 1} {3 - 1} \times \paren {5 + 1} \times \dfrac {7^4 - 1} {7 - 1}\) Divisor Sum of Integer
\(\ds \) \(=\) \(\ds \dfrac {26} 2 \times 6 \times \dfrac {2400} 6\)
\(\ds \) \(=\) \(\ds 13 \times 6 \times 400\)
\(\ds \) \(=\) \(\ds 13 \times \paren {2 \times 3} \times \paren {2^4 \times 5^2}\)
\(\ds \) \(=\) \(\ds 2^5 \times 3 \times 5^2 \times 13\)
\(\ds \) \(=\) \(\ds 31 \, 200\)

$\blacksquare$