Divisor Sum of 20,475
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Example of Divisor Sum of Integer
- $\map {\sigma_1} {20 \, 475} = 45 \, 136$
where $\sigma_1$ denotes the divisor sum function.
Proof
We have that:
- $20 \, 475 = 3^2 \times 5^2 \times 7 \times 13$
Hence:
\(\ds \map {\sigma_1} {20 \, 475}\) | \(=\) | \(\ds \dfrac {3^3 - 1} {3 - 1} \times \dfrac {5^3 - 1} {5 - 1} \times \paren {7 + 1} \times \paren {13 + 1}\) | Divisor Sum of Integer | |||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac {26} 2 \times \dfrac {124} 4 \times 8 \times 14\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 13 \times 31 \times 8 \times 14\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 13 \times 31 \times 2^3 \times \paren {2 \times 7}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 2^4 \times 7 \times 13 \times 31\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 45 \, 136\) |
$\blacksquare$