Divisor Sum of 21,105

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Example of Divisor Sum of Integer

$\map {\sigma_1} {21 \, 105} = 42 \, 432$

where $\sigma_1$ denotes the Divisor sum function.


Proof

We have that:

$21 \, 105 = 3^2 \times 5 \times 7 \times 67$


Hence:

\(\ds \map {\sigma_1} {21 \, 105}\) \(=\) \(\ds \dfrac {3^3 - 1} {3 - 1} \times \paren {5 + 1} \times \paren {7 + 1} \times \paren {67 + 1}\) Divisor Sum of Integer
\(\ds \) \(=\) \(\ds \dfrac {26} 2 \times 6 \times 8 \times 68\)
\(\ds \) \(=\) \(\ds 13 \times 6 \times 8 \times 68\)
\(\ds \) \(=\) \(\ds 13 \times \paren {2 \times 3} \times 2^3 \times \paren {2^2 \times 17}\)
\(\ds \) \(=\) \(\ds 2^6 \times 3 \times 13 \times 17\)
\(\ds \) \(=\) \(\ds 42 \, 432\)

$\blacksquare$