Divisor Sum of 243,760

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Example of Divisor Sum of Integer

$\map {\sigma_1} {243 \, 760} = 620 \, 496$

where $\sigma_1$ denotes the divisor sum function.


Proof

We have that:

$243 \, 760 = 2^4 \times 5 \times 11 \times 277$

Hence:

\(\ds \map {\sigma_1} {243 \, 760}\) \(=\) \(\ds \frac {2^5 - 1} {2 - 1} \times \paren {5 + 1} \times \paren {11 + 1} \times \paren {277 + 1}\) Divisor Sum of Integer
\(\ds \) \(=\) \(\ds 31 \times 6 \times 12 \times 278\)
\(\ds \) \(=\) \(\ds 31 \times \paren {2 \times 3} \times \paren {2^2 \times 3} \times \paren {2 \times 139}\)
\(\ds \) \(=\) \(\ds 2^4 \times 3^2 \times 31 \times 139\)
\(\ds \) \(=\) \(\ds 620 \, 496\)

$\blacksquare$