Divisor Sum of 33,705

From ProofWiki
Jump to navigation Jump to search

Example of Divisor Sum of Integer

$\map {\sigma_1} {33 \, 705} = 67 \, 392$

where $\sigma_1$ denotes the divisor sum function.


Proof

We have that:

$33 \, 705 = 3^2 \times 5 \times 7 \times 107$


Hence:

\(\ds \map {\sigma_1} {33 \, 705}\) \(=\) \(\ds \dfrac {3^3 - 1} {3 - 1} \times \paren {5 + 1} \times \paren {7 + 1} \times \paren {107 + 1}\) Divisor Sum of Integer
\(\ds \) \(=\) \(\ds \dfrac {26} 2 \times 6 \times 8 \times 108\)
\(\ds \) \(=\) \(\ds 13 \times 6 \times 8 \times 108\)
\(\ds \) \(=\) \(\ds 13 \times \paren {2 \times 3} \times 2^3 \times \paren {2^2 \times 3^3}\)
\(\ds \) \(=\) \(\ds 2^6 \times 3^4 \times 13\)
\(\ds \) \(=\) \(\ds 67 \, 392\)

$\blacksquare$